Suppose we have a byte-addressable computer with a cache that holds 8 blocks of 4 bytes each. Assuming that each memory address has 8 bits, to which cache block would the hexadecimal address 0x09 map if the computer uses direct mapping?

Question

Alfred Butler

Computers & Technology

6 May, 16:06

Suppose we have a byte-addressable computer with a cache that holds 8 blocks of 4 bytes each. Assuming that each memory address has 8 bits, to which cache block would the hexadecimal address 0x09 map if the computer uses direct mapping?

+4

Answers (1)

Know the Answer?

Nunez · Answer 1

Block 2

Explanation:

Cache mapping is a technique by which the contents of main memory are brought into the cache memory. we have three different types of cache mapping these are; direct, fully associative and k-way set associative mappings. In direct mapping such as the scenario above, the cache has one block in each set, so it is organized into X = Y sets, as such a particular block of main memory can map to only one particular line of the cache and the formula for determining the line number of cache to which a particular block can map is given by (main memory block address) % (number of lines in cache)