Problem 2 A 10,000 rpm (revolutions per minute) harddisk can transfer data at a rate of 160 Mbps (megabits per second). The time to find a track is negligible. Determine the data amount for which it takes as long to transfer it off the disk as it takes to find the right sector.

491.52 Kb

Explanation:

Number of revolution in a minute ( = 60000 milliseconds) = 10000

Number of revolution in 1 millisecond = 1 / 6

So for a half revolution the time required = 3 milliseconds

Data Transfer = 160 X 1024 Kb/1000 s = 163.84 Kb/milliseconds

Data amount = 163.84 X 3 = 491.52 Kb