Problem 2 A 10,000 rpm (revolutions per minute) harddisk can transfer data at a rate of 160 Mbps (megabits per second). The time to find a track is negligible. Determine the data amount for which it takes as long to transfer it off the disk as it takes to find the right sector.

Question

Justice Curtis

Computers & Technology

2 August, 08:42

Problem 2 A 10,000 rpm (revolutions per minute) harddisk can transfer data at a rate of 160 Mbps (megabits per second). The time to find a track is negligible. Determine the data amount for which it takes as long to transfer it off the disk as it takes to find the right sector.

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Answers (1)

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Jax Abbott · Answer 1

491.52 Kb

Explanation:

Number of revolution in a minute ( = 60000 milliseconds) = 10000

Number of revolution in 1 millisecond = 1 / 6

So for a half revolution the time required = 3 milliseconds

Data Transfer = 160 X 1024 Kb/1000 s = 163.84 Kb/milliseconds

Data amount = 163.84 X 3 = 491.52 Kb