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Write a method swaparrayends () that swaps the first and last elements of its array parameter. ex: sortarray = {10, 20, 30, 40} becomes {40, 20, 30, 10}. the array's size may differ from 4.

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  1. 24 June, 09:54
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    In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:

    #include

    void swaparrayends (int arr[], int nrElements)

    {

    int temp = arr[0];

    arr[0] = arr[nrElements - 1];

    arr[nrElements - 1] = temp;

    }

    void main ()

    {

    int i;

    int myArray[] = { 1,2,3,4,5 };

    int nrElements = sizeof (myArray) / sizeof (myArray[0]);

    swaparrayends (myArray, nrElements);

    for (i = 0; i < nrElements; i++)

    {

    printf ("%d ", myArray[i]);

    }

    getchar ();

    }

    In higher languages like C# it becomes much simpler:

    static void Main (string[] args)

    {

    int[] myArray = {1, 2, 3, 4, 5};

    swaparrayends (myArray);

    foreach (var el in myArray)

    {

    Console. Write (el + " ");

    }

    Console. ReadLine ();

    }

    static void swaparrayends (int[] arr)

    {

    int temp = arr[0];

    arr[0] = arr. Last ();

    arr[arr. Length - 1] = temp;

    }
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