Using for loop. Input an integer and identify whether it's EVEN OR ODD (without using modulo operator)

using only. C+ + programming

Following are the program in c+ + language

#include / / header file

using namespace std; / / namespace

int main ()

{

int n1, i; / / variable declaration

cout<<"Enter Number: ";

cin>>n1; / / input number

for (i=n1; i>1; i=i-2) / / check the condition

{

n1 = n1-2; / / decrement the value of number by - 2

}

if (n1==0) / / check if it is 0

cout<<"number is EVEN"<<"/n"; / / print even

else

cout<<"number is ODD"<<"/n"; / / print odd

return 0;

}

Output:

Enter Number: 45

number is ODD

Again run the program

Enter Number:10

number is EVEN

Explanation:

In this program, we input the number by a user in variable n1. After that, we iterate the for loop and initialize the value of a variable" i" in for loop and check the condition.

In each iteration, the variable n1 is decrement by 2 and store it n1.

Finally, check if n1==0 then it print number is EVEN otherwise it print number is ODD.