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Create an algorithm that will convert dog years to human years using the assumption that 1 dog year = 7 human years. Prompt the user to enter the dog's age in years. Multiply the dog's age by 7 to calculate the human age equivalent of the dog's age. For example, if a dog's age is 2, the calculation should be human age equivalent = 2 * 7, which evaluates to the human equivalent of 14 years old. Output the result to the screen. Write the algorithm using pseudocode, and create a desk check using at least one set of test data.

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  1. 11 January, 02:17
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    Algorithm:

    1. Declare and initialize variable one_dog_year=7.

    2. Ask user to give dog age.

    2.1 Read the dog age and assign it to variable "dog_age".

    3. Create a variable "human_age" to store the equivalent human age.

    3.1 Calculate equivalent human age as "human_age=one_dog_year*dog_age".

    4. Print the equivalent human age of dog age.

    7. End the program.

    / / here is algorithm implemented in c++

    #include

    using namespace std;

    int main ()

    {

    / / initialize one dog year

    int one_dog_year=7;

    int dog_age;

    int equi_h_age;

    cout<<"Enter the dog age:";

    / / read the dog age

    cin>>dog_age;

    //calculate the equivalent human age

    equi_h_age=dog_age*one_dog_year;

    cout<<"equivalent human age is : "<
    return 0;

    }

    Output:

    Enter the dog age:2

    equivalent human age is : 14
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