Write the definition of a function named averager that receives a double parameter and return- - as a double - - the average value that it has been passed so far. So, if you make these calls to averager, averager (5.0), averager (15.0), averager (4.3), the values returned will be (respectively) : 5.0, 10.0, 8.1. Hint: use a static local variable to track the average of all the numbers been called.

Following are the definition of function

double averager (const double &x) / / function definition

{

static double z = 0.0; / / variable declaration

static size_t c = 0;

c=c+1; / / increment of c by 1

z = z + x; / / adding value

return z / c; / / return average

}

Explanation:

Following are the description of statement

Create a function averager of double type that holds a parameter "x" of the double type. In this function we declared a variable "z" of a static double type that value is initialized by 0. The static variable is used to retain value. Declared a variable "c" of size_t type that holds a value 0. After that increment the value of c by 1. adding the value of "z" variable to the "x" and storing the result into the z variable. Finally return the average value