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You are given an array x of string elements along with an int variable n that contains the number of elements in the array. You are also given a string variable mode that has been declared. Assign to mode the mode value of the array. (Assume there are no "ties".)

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  1. 10 June, 19:57
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    Answer and Explanation:

    Make an algorithm of that which include array x of string where Mode of the value of the array means that you have the values such that 1.2,4,2,6,7,8,2 so 2 is the value of set as it appears more than other number similarly when a array of x has been given. First of all initialize a variable then declare it. so for initialization create a variable. Let suppose i create a variable of add and initialize it with 0 and given a it data type integer then

    int add = 0; / / declaration

    int add[]=0; / / declaration and initialization in array

    class add {

    void main (String array[]) {

    int add[]=0; //declaration and instantiation

    int add[] = new int [3];

    add[0]=30; //initialization

    add[1]=80;

    add[2]=20;

    output the given array of string

    for (int i = 0; i
    cout <
    }

    Taking an other example let initialization and declare array of string and print the greater value. For this create a variable with integer data type /

    class Test{

    void main (String[] array) {

    //declaration of array

    int test[][] = new int [2];

    test[0]; new int [2];

    test[1]; new int [4];

    for initialization of array lets take variable a with data type integer

    int a=0;

    //taking loop for condition

    for (int i=0; i
    for (int j=0; j
    //if the loops working properly then take increment in the variable a

    test[i][j] = a++;

    this process repeat until loops got false

    for (int i=0; i
    for (int j=0; j
    cout<
    }

    System. out. println ();

    }

    }
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