Host A and B are communicating over a TCP connection, and Host B has already received from A all bytes up through byte 126. Suppose Host A then sends two segments to Host B back-to-back. The first and second segments contain 80 and 40 bytes of data, respectively. In the first segment, the sequence number is 127, the source port number is 302, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A.

In the second segment sent from Host A to B, what are the sequence number, source port number, and destination port number?

Question

Xzavier Roth

Computers & Technology

11 January, 00:16

Host A and B are communicating over a TCP connection, and Host B has already received from A all bytes up through byte 126. Suppose Host A then sends two segments to Host B back-to-back. The first and second segments contain 80 and 40 bytes of data, respectively. In the first segment, the sequence number is 127, the source port number is 302, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A.

In the second segment sent from Host A to B, what are the sequence number, source port number, and destination port number?

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Answers (1)

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Isabel Saunders · Answer 1

sequence number = 207

source port number = 302

destination port number = 80

Explanation:

The sequence number is 127 + 80 = 207

The source port number is 302, and the destination port number is 80.