Create a method to search an un-ordered array of integers for a value, if the value is found return the index of its position in the array, if not found, return - 1.

Question

Brianna

Computers & Technology

16 June, 05:22

Create a method to search an un-ordered array of integers for a value, if the value is found return the index of its position in the array, if not found, return - 1.

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Answers (1)

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Jaylin Conner · Answer 1

Following are the program in C+ + language

#include / / header file

using namespace std; / / namespace

int search (int s[], int s1, int n) / / function search

{

for (int k = 0; k
{

if (s[k] = = s1) / / searching the element

{

return (k); / / return the index

break;

}

}

return (-1); / / return (-1)

}

int main () / / main function

{

int arr[100], n1, i, s; / / variable declaration

cout<<"Enter number you want in the array:";

cin>>n1;

cout<<"Enter the elements in the array/n ";

for (i = 0; i
{

cin>>arr[i]; / / taking input into the array

}

cout<<"Enter a number you want to search: ";

cin>>s; / / read the serach element by the user

int res = search (arr, s, n1); / / calling function search

cout<
return 0;

}

Output:

Enter number you want in the array:3

Enter the elements in the array

1

2

34

Enter a number you want to search: 2

2

Explanation:

Following are the description of the program

Read the number you want in array in the "n1" variable of int type. Read the array by the user in the "arr ". Read the searching element in the "s" variable. calling the function search by passing array arr, searching element "s" and "n1". In the search function, it returns the index of its position in the array, if not found then it return - 1. Finally print the index.