Suppose a 4096 bit message is sent along a 10Mbit/sec transmission link. Suppose that the latency between the sender and the receive is 4 milliseconds. What is message transmission time?

Answer: 8.1 msec.

Explanation:

If we are told that we have a transmission link of sending 10 Mbits in one second, setting up a direct proportion, we can find out how much time is needed to send 4096 bits along the same channel, as follows:

10⁶ bits = 1 sec

4096 bits = x ⇒ x = 4096 bits. 1 sec / 10⁶ bits = 4.1 msec.

As we have 4 msec of latency between sender and the receiver, we need to add these 4 msec to the transit time, so we have a total message transmission time of 8.1 msec.