Suppose Host A sends two TCP segments back to back to Host B over a TCP connection. The first segment has sequence number 90; the second has sequence number 110.

a. How much data is in the first segment?

b. Suppose that the first segment is lost but the second segment arrives at B. In the acknowledgment that Host B sends to Host A, what will be the acknowledgment number?

Question

Mariah Atkinson

Computers & Technology

12 June, 08:17

Suppose Host A sends two TCP segments back to back to Host B over a TCP connection. The first segment has sequence number 90; the second has sequence number 110.

a. How much data is in the first segment?

b. Suppose that the first segment is lost but the second segment arrives at B. In the acknowledgment that Host B sends to Host A, what will be the acknowledgment number?

+4

Answers (2)

Know the Answer?

Alivia Bartlett · Answer 1

a) Consider sequence numbers, First segment=90

Second segment=110

Data in the first segment = 110-90 = 20

b) Consider the first segment is lost but the second segment arrives at B. In the acknowledgment that Host B sends to Host A, then the acknowledgment number will be first segment of sequence number, that is 90.

Kenny Mathews · Answer 2

(a) 20 bytes

(b) 90

Explanation:

a. 20 bytes.

110-90 = 20 Bytes

Bytes From 90-109 are in the first segment.

b. 90.

TCP uses cumulative acknowledgments, so even if it buffers the second segment, the acknowledgment is still for the first segment.