Ask Question
14 June, 00:08

5. Switch a in the circuit has been open for a long time and switch b has been closed for a long time. Switch a is closed at t = 0. After remaining closed for 1s, switches a and b are opened simultaneously and remain open indefinitely. Determine the expression for the inductor current i that is valid when (a) 0 ≤ t ≤ 1s and (b) t ≥ 1s

+4
Answers (1)
  1. 14 June, 00:14
    0
    (a) 1/L∫Vdt; integral t [0,1]

    (b) 1/L∫Vdt; integral t [ 1, infinity]

    Explanation:

    An Inductor current I, flowing through an inductor depends on the voltage, V, across the inductor and the inductance, L, of the inductor. The switch 1, 2 timing varies the voltage V with time t

    The expression for inductor current is given as:

    I = 1/L∫Vdt,

    where I is equal to the current flowing through the inductor, L is equal to the inductance of the inductor, and V is equal to the voltage across the inductor.

    The formula can also be written as:

    I = I0 + 1/L∫Vdt, where I is inductor current at time t, and io is inductor current at t = 0. Time can be varied by controlling the switch
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “5. Switch a in the circuit has been open for a long time and switch b has been closed for a long time. Switch a is closed at t = 0. After ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers