Ask Question
27 June, 02:40

An n-type semiconductor is known to have an electron concentration of 3 ' 1018 m-3. If the electron drift velocity is 100 m/s in an electric field of 500 V/m. Calculate the mobility and conductivity of this material

+3
Answers (1)
  1. 27 June, 02:46
    0
    Electron Mobility of the material = 0.20 m2/V-s

    Conductivity of the material = 0.096 (Ω-m) - 1

    Explanation:

    Electron mobility = Vd/E

    = 100/500

    = 0.20 m2/V-s

    Conductivity = σ = n |e|μ

    = 3 x 1018 x 1.602 x 10 - 19 x 0.20

    = 0.096 (Ω-m) - 1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An n-type semiconductor is known to have an electron concentration of 3 ' 1018 m-3. If the electron drift velocity is 100 m/s in an ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers