An incompressible fluid flows along a 0.20-m-diameter pipe with a uniform velocity of 3 m/s. If the pressure drop between the upstream and downstream sections of the pipe is 20 kPa, determine the power transferred to the fluid due to fluid normal stresses.

Question

Jay Knox

Engineering

11 November, 13:35

An incompressible fluid flows along a 0.20-m-diameter pipe with a uniform velocity of 3 m/s. If the pressure drop between the upstream and downstream sections of the pipe is 20 kPa, determine the power transferred to the fluid due to fluid normal stresses.

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Answers (1)

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Sage Baird · Answer 1

The power transferred to the fluid is 1.8852 kW

Explanation:

Power = pressure drop * area * velocity

pressure drop = 20 kPa

area = πd^2/4 = 3.142*0.2^2/4 = 0.03142 m^2

velocity = 3 m/s

Power = 20 * 0.03142 * 3 = 1.8852 kJ/s = 1.8852 kW