Ask Question
26 October, 22:43

Lot ABCD between two parallel street lines is 350.00 ft deep and has a 220.00-ft frontage (AB) on one street and a 260.00-ft frontage (CD) on the other. Interior angles at A and B are equal, as are those at C and D. What distances AE and BF should be laid off by a surveyor to divide the lot into two equal areas by means of a line EF parallel to AB?

+3
Answers (1)
  1. 26 October, 22:51
    0
    240.83 ft

    Explanation:

    The distances AE and BF will be equal = 182.58 ft

    The area of the lot will be the product of the depth and the average of the two frontages

    = (350 * (220 + 260) / 2) = 84000 ft

    Half of the area becomes 42000 ft


    Hence 42000=h/2 * (220 + 220 + 2h*tan3.3)

    Solving, we obtain h = 182.28ft

    EF = 220 + (2*182.28*tan 3.3)

    = 240.83ft
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Lot ABCD between two parallel street lines is 350.00 ft deep and has a 220.00-ft frontage (AB) on one street and a 260.00-ft frontage (CD) ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers