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31 October, 21:08

A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of the coil is parallel to the field. What is the emf of the coil

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  1. 31 October, 21:28
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    emf generated by the coil is 1.57 V

    Explanation:

    Given details-

    Number of turns of wire - 1000 turns

    The diameter of the wire coil - 1 cm

    Magnetic field (Initial) = 0.10 T

    Magnetic Field (Final) = 0.30 T

    Time=10 ms

    The orientation of the axis of the coil = parallel to the field.

    We know that EMF of the coil is mathematically represented as -

    E=N (ΔФ/Δt)

    Where E = emf generated

    ΔФ = change inmagnetic flux

    Δt = change in time

    N = no of turns*area of the coil

    Substituting the values of the above variables

    =1000*3.14*0.5*10-4

    =.0785

    E=0.0785 (.2/10*10-3)

    =1.57 V

    Thus, the emf generated is 1.57 V
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