Ask Question
29 December, 02:21

A phone charger requires 0.5 A at 5V. It is connected to a transformer with 100 % of efficiency whose primary contains 2200 turns and is connected to 220-V household outlet.

(a) How many turns should there be in the secondary?

(b) What is the current in the primary?

(c) What would be the output current and output voltage values if number of secondary turns (N2) doubled of its initial value?

+3
Answers (1)
  1. 29 December, 02:27
    0
    a) for transformer which steps down voltage, if V₁ and V₂ be voltage of primary and secondary coil and n₁ and n₂ be the no of turns of wire in them

    V₁ / V₂ = n₁ / n₂

    Here V₁ = 220 V, V₂ = 5V, n₁ = 2200 n₂ = ?

    220 / 5 = 2200 / n₂

    n₂ = 2200 x 5 / 220

    = 50

    b)

    for 100 % efficiency

    input power = output power

    V₁ I₁ = V₂I₂

    I₁ and I₂ are current in primary and secondary coil

    220 x I₁ = 5 x. 5

    I₁ =.01136 A.

    c)

    If n₂ = 100

    V₁ / V₂ = n₁ / n₂

    220 / V₂ = 2200 / 100

    V₂ = 10 V

    V₁ I₁ = V₂I₂

    220 x. 01136 = 10 I₂

    I₂ =.25 A.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A phone charger requires 0.5 A at 5V. It is connected to a transformer with 100 % of efficiency whose primary contains 2200 turns and is ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers