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22 February, 11:57

If the electric field just outside a thin conducting sheet is equal to 1.5 N/C, determine the surface charge density on the conductor.

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  1. 22 February, 12:05
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    The surface charge density on the conductor is found to be 26.55 x 1-6-12 C/m²

    Explanation:

    The electric field intensity due to a thin conducting sheet is given by the following formula:

    Electric Field Intensity = (Surface Charge Density) / 2 (Permittivity of free space)

    From this formula:

    Surface Charge Density = 2 (Electric Field Intensity) (Permittivity of free space)

    We have the following dа ta:

    Electric Field Intensity = 1.5 N/C

    Permittivity of free space = 8.85 x 10^-12 C²/N. m²

    Therefore,

    Surface Charge Density = 2 (1.5 N/C) (8.85 x 10^-12 C²/Nm²)

    Surface Charge Density = 26.55 x 10^-12 C/m²

    Hence, the surface charge density on the conducting thin sheet will be 26.55 x 10^ - 12 C/m².
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