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12 March, 02:59

A glass jar contains 1 red, 3 green, 2 blue, and 4 yellow marbles. If you were to pull one marble out after the other, what would be the probability of getting a blue and then a yellow marble?

8% 9%

10% 11%

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  1. 12 March, 03:14
    0
    9%

    Explanation:

    Data obtained from the question:

    Red (R) = 1

    Green (G) = 3

    Blue (B) = 2

    Yellow (Y) = 4

    Total = 1 + 3 + 2 + 4 = 10

    Probability of getting a blue marble is given by P (B)

    Probability of getting a yellow marble is given by P (Y)

    Probability of getting a blue followed by a yellow marble is given by P (BY)

    From the question given:

    If we were to pull one marble out after the other, the probability of getting a blue and then a yellow marble is illustrated below

    First pull:

    P (B) = 2/10

    2nd pull:

    The total is 9, therefore P (Y) = 4/9

    P (BY) = P (B) x P (Y)

    P (BY) = 2/10 x 4/9

    P (BY) = 8/90 = 0.09

    Multiply by 100 to express in percent

    P (BY) = 0.09 x 100 = 9%

    Therefore, the probability of getting a blue and then a yellow marble is 9%
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