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12 October, 17:29

The velocity profile for a thin film of a Newtonian fluid that is confined between the plate and a fixed surface is defined by u = (5y-0.5y2) mm/s where y is in mm. Determine the force P that must be applied to the plate to cause this motion. The plate has a surface area of 4000mm2 in contact with the fluid. Take µ = 0.55 N. s/m2

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  1. 12 October, 19:15
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    F = 0.0022N

    Explanation:

    Given:

    Surface area (A) = 4,000mm² = 0.004m²

    Viscosity = µ = 0.55 N. s/m²

    u = (5y-0.5y²) mm/s

    Assume y = 4

    Computation:

    F/A = µ (du/dy)

    F = µA (du/dy)

    F = µA[ (d/dy) (5y-0.5y²) ]

    F = (0.55) (0.004) [ (5-1 (4)) ]

    F = 0.0022N
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