A series circuit contains five resistors. The total voltage applied to the circuit is 120 V. Four resistors have voltage drops of 35 V, 28 V, 22 V, and 15 V. What is the voltage drop of the fifth resistor?

V₅ = 20 V

Explanation:

Given that

Total voltage, V = 120 V

Given that resistor are connected in series that is why the total voltage drop will be summation of voltage drop in the all resistor.

V₁=Voltage drop on first resistor

V₂=Voltage drop on second resistor

V₃=Voltage drop on third resistor

V₄=Voltage drop on forth resistor

V₅=Voltage drop on fifth resistor

Therefore

V = V₁+V₂+V₃+V₄+V₅

120 = 35 + 28 + 22 + 15 + V₅

V₅ = 20 V

Therefore the voltage drop on the fifth resistor will be 20 V.