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8 January, 01:04

An electric winch operates on 140 volts [V] and draws 6 amperes [A] of current. The winch has an efficiency of 64 %. The winch is used to lift an object that weighs 510 pound-force [lb Subscript f ] for 11 seconds [s]. Determine the height the object is lifted to, in units of meters [m].

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  1. 8 January, 01:14
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    efficiency = (energy output / energy input)

    energy input = ivt where i is current = 6 A, v is volts = 140 and t time = 11 seconds

    energy input = 6 * 140 * 11 = 9240 J

    energy output = 0.64 * 9240 = 5913.6 J

    510 pound-force = 2268.593 N

    at height h, potential energy = mgh = 5913.6 J

    2268.593 * h = 5913.6

    h = 5913.6 / (2268.593) = 2.61 m
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