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1 August, 11:04

The current in a 67-Ω resistor is 0.12 A. This resistor is in series with a 35-Ω resistor, and the series combination is connected across a battery. What is the battery voltage?

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  1. 1 August, 11:10
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    Resistor in series = R1+R2

    Thus - 57+35 = 92ohms

    Voltage - IR

    0.12*92 = 11.04V
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