Ask Question
7 April, 03:04

4. A 1 m3 rigid tank has propane at 100 kPa, 300 K and connected by a valve to another tank of 0.5 M3 with propane at 250 kPa, 400 K. The valve is opened and the two tanks come to a uniform state at 325 K. What is the final pressure?

+3
Answers (1)
  1. 7 April, 03:23
    0
    139.97 kPa

    Explanation:

    Assuming propane is an ideal gas

    PV = nRT

    n₁ (number of mole f the first gas) of the 1 m³ rigid tank = P₁V₁ / RT₁ R gas constant = 8.314 J/mol

    n₁ = 100kPa * 1 m³ / (8.314 J/mol * 300 K) = 0.0401 mol

    n₂ = 0.5 m³ * 250 kPa / (8.314J/mol * 400 K) = 0.0376 mol where n₂ is the number of mole of the second gas

    n total = n₁ + n₂ = 0.0401 mol + 0.0376 mol = 0.0777 mol

    PV = nRT

    P final pressure = nRT / V where V = V₁ + V₂ = 1 m³ + 0.5 m³ = 1.5 m³

    P final pressure = 0.0777 mol * 8.314 J/mol * 325 K / 1.5 m³ = 139.97 kPa
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “4. A 1 m3 rigid tank has propane at 100 kPa, 300 K and connected by a valve to another tank of 0.5 M3 with propane at 250 kPa, 400 K. The ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers