Ask Question
14 September, 17:58

A viscous fluid flows in a 0.10-m-diameter pipe such that its velocity measured 0.012 m away from the pipe wall is 0.8 m/s. If the flow is laminar, determine the centerline velocity and the flowrate.

+4
Answers (1)
  1. 14 September, 18:10
    0
    A) centerline velocity = 1.894 m/s

    B) flow rate = 7.44 x 10^ (-3) m³/s

    Explanation:

    A) The flow velocity intensity for the input radial coordinate "r" is given by;

    U (r) = (Δp•D²/16μL) [1 - (2r/D) ²]

    Velocity at the centre of the tube can be expressed as;

    V_c = (Δp•D²/16μL)

    Thus,

    U (r) = (V_c) [1 - (2r/D) ²]

    From question, diameter = 0.1m, thus radius (r) = 0.1/2 = 0.05m

    But we are to find the velocity at the centre of the tube, thus;

    We will use the radius across the horizontal distance which will be;

    0.05 - 0.012 = 0.038m

    Thus, let's put 0.038 for r in the velocity intensity equation and put other relevant values to get the velocity at the centre.

    Thus;

    U (r) = (V_c) [1 - (2r/D) ²]

    0.8 = (V_c) [1 - { (2 * 0.038) / 0.1}²]

    0.8 = (V_c) [1 - (0.76) ²]

    V_c = 0.8/0.4224 = 1.894 m/s

    B) flow rate is given by;

    ΔV = Average Velocity x Area

    Now, average velocity = V_c/2

    Thus, average velocity = 1.894/2 = 0.947 m/s

    Area (A) = πr² = π x 0.05² = 0.007854 m²

    So, flow rate = 0.947 x 0.007854 = 7.44 x 10^ (-3) m³/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A viscous fluid flows in a 0.10-m-diameter pipe such that its velocity measured 0.012 m away from the pipe wall is 0.8 m/s. If the flow is ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers