Ask Question
24 January, 10:21

Given the following materials and their corresponding thermal conductivity values, list them in order from most conductive to least conductive. Sheet Rock: k = 0.43 W / (m*K) Masonite: k = 0.047 W / (m*K) Glass: k = 0.72 W / (m*K) Lexan: k = 0.19 W / (m*K) b) Given the following information, calculate the thermal conductivity using Fourier's Equation. q = 100 WA = 8 m^2ATΔT = 10L = 7 m

+4
Answers (1)
  1. 24 January, 10:37
    0
    1) Glass

    2) Rock sheet

    3) Lexan

    4) Masonite

    b) k = 8.75 W/m. K

    Explanation:

    Given:

    The thermal conductivity of certain materials as follows:

    -Sheet Rock: k = 0.43 W / (m*K)

    -Masonite: k = 0.047 W / (m*K)

    -Glass: k = 0.72 W / (m*K)

    -Lexan: k = 0.19 W / (m*K)

    Data Given:

    - Q = 100 W

    - A = 8 m^2

    - dT = 10 C

    - L = 7 m

    Find:

    a) list the materials in order from most conductive to least conductive

    b) calculate the thermal conductivity using Fourier's Equation

    Solution:

    - We know from Fourier's Law the relation between Heat transfer and thermal conductivity as follows:

    Q = k*A*dT / L

    - From the relation above we can see that rate of heat transfer is directly proportional to thermal conductivity k.

    - Hence, the list in order of decreasing conductivity is as follows:

    - The list of materials in the decreasing order of thermal conductivity k is:

    1) Glass k = 0.72 W/m. K

    2) Rock sheet k = 0.43 W/m. K

    3) Lexan k = 0.19 W/m. K

    4) Masonite k = 0.047 W/m. K

    - Use the relation given above we can compute the thermal conductivity k with the given dа ta:

    k = Q*L / (A*dT)

    k = (100 W * 7 m) / (8 m^2*10 C)

    k = 8.75 W/m. K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Given the following materials and their corresponding thermal conductivity values, list them in order from most conductive to least ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers