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19 November, 20:13

One cycle of the power dissipated by a resistor (R=800 Ω) is given by

P (t) = 0.03125 W, 0≤t<12.0 sP (t) = 0.03125 W, 0≤t<12.0 s

P (t) = 0 W, 12.0≤t<30 sP (t) = 0 W, 12.0≤t<30 s

This periodic signal repeats in both directions of time.

What is the amplitude of the PWM voltage signal applied across the 800-Ω resistor?

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  1. 19 November, 20:19
    0
    Maximum voltage = 5 V

    Explanation:

    The maximum power from the resistor is evidently 0.03125W in the time periods given.

    And Power dissipated from electric circuits is given by

    P = IV

    V = IR

    P = I (IR) = I²R

    Since I = (V/R), power can also be expressed as

    P = IV = (V/R) V = V²/R

    Since the resistance of the resistor isn't variable, then the variable here has to be the voltage, So, to calculate maximum voltage,

    R = 800 ohms, P = 0.03125 W

    0.03125 = V²/800

    V² = 25

    V = 5V
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