A household refrigerator runs one-fourth of the time and removes heat from the food compartment at an average rate of 800 kJ/h. If the COP of the refrigerator is 2.4, determine the power the refrigerator draws when running.

The power the refrigerator draws when running = 0.37 Kw

Explanation:

Since the household refrigerator runs one-fourth of the time;

The refrigerator will remove heat at the rate of;

QL = 4 x (800 Kj/h) = 3200 Kj/h

The formula to determine the power the refrigerator draws when running is;

W (in) = QL/COP

Thus;

W (in) = 3200/2.4 = 1333.33 Kj/h

This is in Kj/h and the unit of Power is in kw. We know that 1kw = 3600 kj/h

Thus;

1333.33Kj/h = (1333.33Kj/h x 1kw) / 3600 kj/h = 0.37 kw