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11 April, 08:18

melinda is using a rectangular brass bar in a sculpture she is creating. the brass bar has a length that is 4 more than 3 times its width if the area of the rectangular brass bar is 480 inches what are the dimensions answer

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  1. 11 April, 08:24
    0
    The dimension of Length = L

    The dimension of width = L

    The dimension of Area = L²

    Explanation:

    A dimension is one of the physical properties that are regarded as fundamental measures of a physical quantity, such as mass, length and time.

    L - length, W - width, A - Area

    A = W * L (Formula for Area)

    Given:

    L = 4 + 3W (length that is 4 more than 3 times its width)

    Area = 480 inches

    A = W * L

    Sub. Given into Formula of Area

    480 = W (4 + 3W)

    480 = 4W + 3W²

    3W² + 4W - 480 = 0

    a=3 b=4 c = - 480

    where W = unknown using the quadratic equation

    W = - b ± √ (b² - 4ac) / 2a

    W = - 4 ± √ (4² - 4.3.-480) / 2.3

    W = - 4 ± √ (16 + 5760) / 6

    W = - 4 ± √ (5776) / 6

    W = (-4 ± 76) / 6

    W = (-4 + 76) / 6 or (-4-76) / 6

    W = 72/6 or - 80/6

    W = 12 or - 13.6

    We choose w=12 inches

    Sub. W into L

    L = 4 + 3W

    L = 4 + 3*12

    L = 40 inches

    Area = W * L

    = 40 inches * 12 inches

    Area = 480 inches ²

    Dimension wise

    The dimension of Length = L

    The dimension of width = L

    The dimension of Area = L²
  2. 11 April, 08:27
    0
    180 x 60 inches

    Width = 60 inches

    Length = 180 inches

    Explanation:

    Given

    Let L = Length

    W = Width

    P = Perimeter

    Length = 3 * Width

    L = 3W

    Perimeter of Brass = 480 inches

    P = 480

    Perimeter is given as 2 (L + W);

    So, 2 (L + W) = 480

    L + W = 480/2

    L + W = 240

    Substitute 3W for L; so,

    3W + W = 240

    4W = 240

    W = 240/4

    W = 60 inches

    L = 3W

    L = 3 * 60

    L = 180 inches
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