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26 April, 01:58

an electric heater consumes 3.6MJ when connected to a 250V supply for 40minutes find the power rating of the heater and the current taken from supply

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  1. 26 April, 02:08
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    Power rating of heater=1.5kw

    Current taken from the supply=6A

    Explanation:

    Power (P) = Energy/Time

    Where, electrical energy=3.6*10^6J and Time=40mins=40*60s

    P=3.6*10^6J/40*60s

    P=1500J/s or 1500watts

    P=1.5kw

    Current supply:

    P=VI

    Where, power (P) = 1500watts, Voltage supply (V) = 250volts, and current (I) = ?

    Making current (I) the subject of the formula:

    I=P/V

    I=1500watts/250volts=6A

    Therefore, current taken from the supply is 6A.
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