How much would a 10.0 inch long, 0.25 inch diameter AISI 1020 Q&T bolt stretch when loaded with 2000 lbs?

0.014 in

Explanation:

The Young's module of steel is of E = 210 GPa = 30*10^6 psi

The section of the bolt would be:

A = π/4 * D^2

The stiffness would be:

k = E * A / L

k = π * D^2 * E / (4 * L)

k = π * 0.25^2 * 30*10^6 / (4 * 10) = 147000 lb / in

If I apply a force of 2000 lb, I calculate the stretching with Hooke's law:

Δx = f / k

Δx = 2000 / 147000 = 0.014 in