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29 April, 20:28

Base course aggregate has a target dry density of 119.7 Ib/cu ft in place. It will be laid down and compacted in a rectangular street repair area of 2000 ft by 48 ft by 6 in. The aggregate in the stockpile contains 3.1 percent moisture. If the required compaction is 95% of the target, how many tons of aggregate will be needed?

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  1. 29 April, 20:35
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    total weight of aggregate = 5627528 lbs = 2814 tons

    Explanation:

    we get here volume of space to be filled with aggregate that is

    volume = 2000 * 48 * 0.5

    volume = 48000 ft³

    now filling space with aggregate of the density that is

    density = 0.95 * 119.7

    density = 113.72 lb/ft³

    and dry weight of this aggregate is

    dry weight = 48000 * 113.72

    dry weight = 5458320 lbs

    we consider here percent moisture is by weigh

    so weight of moisture in aggregate will be

    weight of moisture = 0.031 * 5458320

    weight of moisture = 169208 lbs

    so here total weight of aggregate is

    total weight of aggregate = 5458320 + 169208

    total weight of aggregate = 5627528 lbs = 2814 tons
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Home » Engineering » Base course aggregate has a target dry density of 119.7 Ib/cu ft in place. It will be laid down and compacted in a rectangular street repair area of 2000 ft by 48 ft by 6 in. The aggregate in the stockpile contains 3.1 percent moisture.
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