If p is a pressure, V a velocity, and a fluid density, what are the dimensions (in the MLT system) of (a) p/, (b) pV, and (c) p/pV2?

Answer:p=ML^-1T^-2

b) PV=MT^-3

c) P/PV^2=T^2L^-2

Explanation:In dimensions, Mass in kg is represented by M

Length is represented by L in meters.

T represent Time in seconds, s.

Pressure=hpg, h=height or depth In m, a=density=kg/m^3

g=acceleration due to gravity, m/s^2

P=hag=mxkg/m^3 xm/s^2=m^2*kg/m^2*s^2=kgm^-1 s^-2=ML^-1T^-2

B) PV=pressure xvelocity

=ML^-1T^-2*distance/time

ML^-1T^-2*L/T=MT^-3

C) p/pv^2=1/V^2 = (time/distance) ^2 = (T/L) ^2=T^2L^-2