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3 October, 17:26

A consultant has proposed that a pulse-jet baghouse with bags that are 15 cm in diameter and 5 m in length. Estimate the net number of bags required if the manufacturer's recommended air-to-cloth ratio for aggregate plants in 0.05 m/s, and a requirement that 1/8 of the bags are off-line for cleaning

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  1. 3 October, 17:41
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    0,5 bags

    Total number of bags = 0.5 + 4 = 4.5 bags or 5 bags

    Explanation:

    Convert 15cm to meters = 15/100 = 0.15m

    Flow rate Q = Area x velocity

    = π d x v

    = π (0.15) x 1

    = 0.4712

    A = Q/v = 0.4712 / 0.05

    = 9.435 m^2

    The net number of bags = A/π dh

    = 9.425/π (0.15) (5)

    = 4 bags

    Requirement that 1/8 of the bags are off-line for cleaning

    = Net number of bags / 8

    = 4/8

    = 0.5 bag or 1bag

    Total number of bags

    = 4bags + 1bag

    = 5bags
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