A vehicle has a weight of 5,000 and a rear static weight on wheels of 2,542, both measured in lbf. Of the wheelbase is 93 inches and the vertical center of gravity is 50 inches, calculate the number of "gs" of acceleration the vehicle must experience in order for the front wheels to lift off the ground.

The number of "gs" of acceleration the vehicle must experience in order for the front wheels to lift off the ground is 1.844 gs.

Explanation:

To solve the question, we assume that the center of gravity is acting at the center midway of the car, half the wheel base. That is at 93/2 inches

Since the weight is acting at the center of gravity then we have taking moment about the rear wheel gives

(5000 - 2542) * 7.75 + 5000 * 7.75/2 = 5000/32.2 * a * ‪4.166667‬

Which gives

38424.5 = 646.99798*a

a = 38424.5 / 646.99798 = 59.39 f/s² which is equivalent to

59.39 / 32.2 or 1.844 gs