0.3 kg air inside 42.9 litres cylinder has a temperature is 31.0°C. The R value for air = 287 J/kg/K. What is the pressure of air inside the cylinder? (k Pascal)

Pressure = 610.125 kPa

Explanation:

Given:

Mass of the air, m = 0.3 kg

Volume of the cylinder, V = 42.9 litres = 42.9 * 10⁻³ m³

R value for the air = 287 J/kg/K

Temperature, T = 31.0° C = 304 K

Now,

we know the ideal gas equation is given as:

PV=mRT

where,

P is the pressure

on substituting the values, in the above formula

we get

P * 42.9 * 10⁻³ = 0.3 * 287 * 304

or

P = 610125.87 Pa

or

P = 610.125 kPa