A cast-iron pipe 2.0 ft in diameter and 200 ft long joins two water (60°F) reservoirs. The upper reservoir has a water-surface elevation of 155 ft, and the lower on has a water-surface elevation of 45 ft. The pipe exits from the side of the upper reservoir at an elevation of 120 ft and enters the lower reservoir at an elevation of 25 ft. There are two wide-open gate valves in the pipe.

Question

Elisha

Engineering

19 October, 02:45

A cast-iron pipe 2.0 ft in diameter and 200 ft long joins two water (60°F) reservoirs. The upper reservoir has a water-surface elevation of 155 ft, and the lower on has a water-surface elevation of 45 ft. The pipe exits from the side of the upper reservoir at an elevation of 120 ft and enters the lower reservoir at an elevation of 25 ft. There are two wide-open gate valves in the pipe.

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Answers (1)

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Lorelei Camacho · Answer 1

23,627.4 ft

Explanation:

44,580 x 47 %

44,580 x. 47 = 20,952.6

So, the water decreased 20,952.6 ft

If you want the water level after the drought just subtract.

44,580 - 20,952.6 = 23,627.4 ft