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15 May, 13:34

100 kg of R-134a at 200 kPa are contained in a piston-cylinder device whose volume is 12.322 m3. The piston is now moved until the volume is one-half its original size. This is done such that the pressure of the R-134a does not change. Determine the final temperature and the change in the total internal energy of the R-134a.

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  1. 15 May, 13:56
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    T=151 K, U=-1.848*10^6J

    Explanation:

    The given process occurs when the pressure is constant. Given gas follows the Ideal Gas Law:

    pV=nRT

    For the given scenario, we operate with the amount of the gas - n - calculated in moles. To find n, we use molar mass: M=102 g/mol.

    Using the given mass m, molar mass M, we can get the following equation:

    pV=mRT/M

    To calculate change in the internal energy, we need to know initial and final temperatures. We can calculate both temperatures as:

    T=pVM / (Rm); so initial T=302.61K and final T=151.289K

    Now we can calculate change of U:

    U=3/2 mRT/M using T - difference in temperatures

    U=-1.848*10^6 J

    Note, that the energy was taken away from the system.
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