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20 June, 08:36

The velocity of a particle along the s-axis is given by v=5s^ (3/2), where s is in mm and v is in mm/s. If the particle starts from rest, determine the acceleration when s is 2 mm. Express answer in mm/s^2

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  1. 20 June, 08:56
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    Answer: 150mm/s^2

    Explanation:

    S=2mm

    V=5S^ (3/2)

    Acceleration (a) = dv/dt

    a=5*3/2*S^1/2 (ds/dt)

    a=15/2*S^1/2 (V)

    a=7.5*S^1/2 (5S^3/2)

    a = (7.5) * (5) * (S^2)

    a = (7.5) * (5) * (4) = 150mm/s^2.
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