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23 October, 18:39

If water molecules pass through a membrane with a steady state flux of 220 mole / (m2 day), how long will it take, in hours, for 0.400 kg of water to pass through a 565 square centimeter of the membrane?

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  1. 23 October, 18:47
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    0.0386 hr

    Explanation:

    Area = 565 cm^2 = 0.0565 m^2 (1 cm^2 = 0.0001 m^2)

    flux state rate = 220 mole/m^2-day

    There are 24 hrs in a day, therefore rate in hrs will be

    220/24 = 9.17 mole/m^2-hr

    mass of water = 0.4 kg

    molar mass of water = (1 x 2) + 16 = 18 kg/mole

    therefore,

    mole of water = mass of water/molar mass of water

    mole of water = 0.4/18 = 0.02 mole

    mole flux = mole/area = 0.02/0.0565 = 0.354 mol/m^2

    time that will be taken will be for water to pass = mole flux/mole flux rate

    time = 0.354/9.17 = 0.0386 hr
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