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15 April, 05:01

An element has two naturally occurring isotopes, isotope 1 with an atomic weight of 78.918 amu and isotope 2 with an atomic weight of 80.916 amu. If the average atomic weight for the element is 79.903 amu, calculate the fraction of occurrences of these two isotopes.

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  1. 15 April, 05:11
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    The fraction of isotope 1 is 50.7 % and fraction fraction of isotope 1 is 49.2 %.

    Explanation:

    Given that

    Weight of isotope 1 = 78.918 amu

    Weight of isotope 2 = 80.916 amu

    Average atomic weight = 79.903 amu

    Lets take fraction of isotope 1 is x then fraction of isotope 2 will be 1-x.

    The total weight will be summation of these two isotopes

    79.903 = 78.918 x + 80.916 (1-x)

    By solving above equation

    80.916 - 79.903 = (80.916-78.918) x

    x=0.507

    So the fraction of isotope 1 is 50.7 % and fraction fraction of isotope 1 is 49.2 %.
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