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2 November, 22:00

Calculate the fraction of atom sites that are vacant for lead at its melting temperature of 327°C (600 K). Assume an energy for vacancy formation of 0.55 eV/atom.

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  1. 2 November, 22:21
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    Fraction of atom sites, Nv/N = 2.41*10^-5

    Explanation:

    Nv/N = exp (-Qv/kT)

    Nv/N = exp[ - (0.55ev/atom) / (8.62*10^-5ev/atom) (600k) ]

    Nv/N = 2.41*10^-5
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