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24 May, 07:35

A DC generator turns at 2000 rpm and has an output of 200 V. The armature constant is 0.5 V-min/Wb, and the field constant of the machine is 0.02 H. What is most nearly the field current produced by the generator? a) 4.0 A b) 10 A c) 1000 A d) 4000 A

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Answers (2)
  1. 24 May, 07:46
    0
    b. 10A

    Explanation:

    Using the formula, E = k * r*I

    200 = 0.5 * 2000*0.02*I

    200=20*I

    Dividing with 20

    I = 200/20 = 10A
  2. 24 May, 07:46
    0
    10 A (B)

    Explanation:

    output of the DC generator = 200 V

    revolution = 2000 rpm

    Armature constant = 0.5 V-min/Wb

    field constant = 0.02 H

    i = field current

    output of a DC generator = (rpm) * (armature constant) * (field constant) * i

    200 = 2000 * 0.5 * 0.02 * i

    200 = 20 i

    therefore i = 200 / 20 = 10 A
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