A rectangular concrete (n=0.013) channel 20 feet wide, on a 2.5% slope, is discharging 400 ft3 / sec into a stilling basin. The stilling basin is also 20 feet wide and has a water depth of 8 ft determined from the downstream channel condition. What is the length of the stilling basin? What is the height of the endsill?

Length of stilling basin = 32.9 feet

Height of end sill = 6.58 feet

Explanation:

Discharge = Q = 400 ft^3 / sec

Slope = 2.5 ft

Width = 20 feet

n = 0.013

we will assume the depth of flow as "d"

Q = 1/n (R) ^2/3 (slope) ^1/2 A (here R is the hydraulic Radius)

by substituting the given data in above formula we get:

400 = 1/0.013 * (R) ^2/3 * sqrt (2.5/100) * 20d

R = A/P

here, A is the flow area and P is the wetted perimeter

400*0.013 = (20d / (20+20d)) ^2/3 * sqrt (2.5/100) * 20d

d = 1.42 feet

Depth of stilling channel before the jump will be = d1 = 8 feet

Depth of stilling channel after the jump will be = d2 = 1.42 feet

Length of stilling basin = 5 (d2 - d1)

= 5 (8 - 1.42)

Length of stilling basin = 32.9 feet

Now calculating the height of end sill:

Jump height = (8 - 1.42)

Height of end sill = 6.58 feet