John paid $34 for two algebra and three geometry books. He paid $36 for three algebra and two geometry books. What is the cost of each book?

Let the price of single algebra book = x

and the price of geometry book = y

Then equation (1) = 2x+3y=34

3y = (34 - 2x)

y = (34 - 2x) / 3

And equation (2) = 3x + 2y=36

put value of y in equation (2)

3x + 2 (34-2x) / 3 = 36

9x + 2 (34-2x) = 108

9x + 68 - 4x=108

5x=40

x=8

put x=8 in equation (1)

2 (8) + 3y = 34

16+3y=34

3y=18

y=6

Hence, price of algebra book = 8$ and price of geometry book=6$