The acceleration of a particle is directly proportional to the square of Problems 615

the time t. When t 5 0, the particle is at x 5 24 m. Knowing that at

t 5 6 s, x 5 96 m and v 5 18 m/s, express x and v in terms of t. ((mechanics))

Question

7 January, 06:19

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Tobias Burton · Answer 1

Answer

x (t) = t^4/108 + 10t + 24, v (t) = t^3/27 + 10

The acceleration of a particle is directly proportional to the square of Problems 615the time t. When t 5 0, the particle is at x 5 24 m. Knowing that att 5 6 s, x 5 96 m and v 5 18 m/s, express x and v in terms of t. ((mechanics))