What is the pH of 0.001 mol dm-3 solution of sodium hydroxide

I'm pretty sure it would be 11

explanation: [H+] [OH-] = 10-14

[H+] = 10-14/[OH-] = 10-14 / (1 * 10-3) = 10-11

pH = - Log10[H+]

= - Log10[10-11] = - 1 * - 11 Log10[10-11] = 1 = - 1 * - 11 * 1 = 11

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