In ΔJKL, solve for x. Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle L measures 27 degrees.

J = 27°

K = 90°

L = 90° - 27° = 63°

x is the hypotenuse.

34 is the short leg or opposite

the long leg is the adjacent

sine Θ = opposite / hypotenuse

sine 27° = 34 / x

sin (27°) * x = 34

x = 34 / sin (27°)

x = 34 / 0.45399

x = 74.89

Answer is B.) 74.89