A footpath is to be constructed in a park in the shape of a parallelogram. When a coordinate plane is laid over a map of the park, the vertices of the footpath are (-4,2) (8,2) (11,7) and (-1,7). What is the perimeter of this path

Question

Jovany Castillo

Geography

26 January, 18:20

A footpath is to be constructed in a park in the shape of a parallelogram. When a coordinate plane is laid over a map of the park, the vertices of the footpath are (-4,2) (8,2) (11,7) and (-1,7). What is the perimeter of this path

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Answers (2)

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Braxton Barrera · Answer 1

Answer: perimeter = 35.66 units

Explanation:

AB=8 - (-4) = 12

CD=11 - (-1) = 12

BD=√ (11-8) ² + (7-2) ² = √=34

AC=√ (-1 - (-4)) ² + (7-2) ² = √=34

Perimeter = AB + CD + BD + AC

perimeter=2*12+2√34 = 24+2√34 = 35.66 units

Tucker Newton · Answer 2

Tucker Newton 26 January, 18:44

0

I believe the answer is A