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7 May, 20:22

a motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels in this time.

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  1. 7 May, 20:47
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    S = 20.46m

    Explanation:

    According to Second Law of Motion:

    S = Vi*t + 0.5*a*t^2

    dа ta:

    Vi = 3m/s

    a = 9.3m/s^2

    t = 1.8s

    S = ?

    Solution:

    S = 3*1.8 + 0.5*9.3*1.8^2

    S = 5.4 + 15.06

    S = 20.46m
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